If G is a subgroup of finite index in the multiplicative group of an infinite field K then G - G = K. Similar results hold for various rings. Journal Information This monthly journal, begun in 1950, ...
Let $D$ be a skew field, $D^\ast$ its multiplicative group and $H \triangleleft D^\ast$. Then $H$ contains a noncyclic free subgroup $F$, provided that there exists a ...
Some results have been hidden because they may be inaccessible to you
Show inaccessible results
Feedback